分享几个简单易懂的Python技巧，能够极大的提高工作效率哦！
今天和大家来分享几个关于Python的分享小技巧，都是个简高工非常简单易懂的内容，希望大家看了之后能够有所收获。单易懂的的提
01. 将字符串倒转
my_string = "ABCDE" reversed_string = my_string[::-1] print(reversed_string) -------------------------------------- # Output # EDCBA02. 将英文单词的技巧极首字母大写
通过title()方法来实现首字母的大写
my_string = "my name is xiao ming" # 通过title()来实现首字母大写 new_string = my_string.title() print(new_string) ------------------------------------- # output # My Name Is Xiao Ming03. 给字符串去重
my_string = "aabbbbbccccddddeeeff" # 通过set()来进行去重 temp_set = set(my_string) # 通过join()来进行连接 new_string = .join(temp_set) print(new_string) -------------------------------- # output # dfbcae04. 拆分字符串
Python split()通过指定分隔符对字符串进行切片，默认的作效分隔符是网站模板" "
string_1 = "My name is xiao ming" string_2 = "sample, string 1, string 2" # 默认的分隔符是空格，来进行拆分 print(string_1.split()) # 根据分隔符"，分享"来进行拆分 print(string_2.split(,个简高工)) ------------------------------------ # output # [My, name, is, xiao, ming] # [sample, string 1, string 2]05. 将字典中的字符串连词成串
list_of_strings = [My, name, is, Xiao, Ming] # 通过空格和join来连词成句 print( .join(list_of_strings)) ----------------------------------------- # output # My name is Xiao Ming06. 查看列表中各元素出现的个数
from collections import Counter my_list = [a,a,b,b,b,c,d,d,d,d,d] count = Counter(my_list) print(count) # Counter({ d: 5, b: 3, a: 2, c: 1}) print(count[b]) # 单独的“b”元素出现的次数 # 3 print(count.most_common(1)) # 出现频率最多的元素 # [(d, 5)]07. 合并两字典
dict_1 = { apple: 9, banana: 6} dict_2 = { grape: 4, orange: 8} # 方法一 combined_dict = { **dict_1, **dict_2} print(combined_dict) # 方法二 dict_1.update(dict_2) print(dict_1) # 方法三 print(dict(dict_1.items() | dict_2.items())) --------------------------------------- # output # { apple: 9, banana: 6, grape: 4, orange: 8} # { apple: 9, banana: 6, grape: 4, orange: 8} # { apple: 9, banana: 6, grape: 4, orange: 8}08. 查看程序运行的时间
import time start_time = time.time() ######################## # 具体的程序.......... ######################## end_time = time.time() time_taken_in_micro = (end_time- start_time) * (10 ** 6) print(time_taken_in_micro)09. 列表的服务器租用扁平化
有时候会存在列表当中还嵌套着列表的情况，
from iteration_utilities import deepflatten l = [[1,单易懂的的提2,3],[4,[5],[6,7]],[8,[9,[10]]]] print(list(deepflatten(l, depth=3))) ----------------------------------------- # output # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]10. 查看列表当中是否存在重复值
def unique(l): if len(l)==len(set(l)): print("不存在重复值") else: print("存在重复值") unique([1,2,3,4]) # 不存在重复值 unique([1,1,2,3]) # 存在重复值11. 数组的转置
array = [[a, b], [c, d], [e, f]] transposed = zip(*array) print(list(transposed)) ------------------------------------------ # output # [(a, c, e), (b, d, f)]12. 找出两列表当中的不同元素
def difference(a, b): setset_a = set(a) setset_b = set(b) comparison = set_a.difference(set_b) return list(comparison) # 返回第一个列表的不同的元素 difference([1,2,6], [1,2,5]) # [6]13. 将两列表变成键值对
将两个列表合并成一个键值对的字典
def to_dictionary(keys, values): return dict(zip(keys, values)) keys = ["a", "b", "c"] values = [2, 3, 4] print(to_dictionary(keys, values)) ------------------------------------------- # output # { a: 2, b: 3, c: 4}14. 对字典进行排序
根据字典当中的值对字典进行排序
d = { apple: 9, grape: 4, banana: 6, orange: 8} # 方法一 sorted(d.items(), key = lambda x: x[1]) # 从小到大排序 # [(grape, 4), (banana, 6), (orange, 8), (apple, 9)] sorted(d.items(), key = lambda x: x[1], reverse = True) # 从大到小排序 # [(apple, 9), (orange, 8), (banana, 6), (grape, 4)] # 方法二 from operator import itemgetter print(sorted(d.items(), key = itemgetter(1))) # [(grape, 4), (banana, 6), (orange, 8), (apple, 9)]